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  • in reply to: A little [1] [2] [3]-problem #4126
    Girl Power
    Participant

    OK, so to say it in short: The two approaches only differ by approximately ½% and rerolling all 5 dice is slightly better than rerolling two dice. I understand that this type of calculations should be done with a little programming. Anyhow, thanks so far!

    in reply to: A little [1] [2] [3]-problem #4117
    Girl Power
    Participant

    Still interested, that would be fun to see!

    in reply to: Trailer #3191
    Girl Power
    Participant

    Just saying: GIRL POWER!

    in reply to: Example: How to get the result 6? #2053
    Girl Power
    Participant

    John: See https://www.inverteddice.com/topic/first-question/. The chance is 750/7776 which is approximately 9.6451%

    in reply to: A little [1] [2] [3]-problem #1943
    Girl Power
    Participant

    Just realized, that if I choose to reroll all 5 dice, I still have the possibility of achieving both five sixes and combinations of only ones and fives OR only twos and fours. So, the problem should be stated like this:
    Is the probability of getting [6] [6] with TWO dice in two rolls higher than the sum of the probabilities of achieving the following combinations with FIVE dice in two rolls?
    [6] [6] [6] [6] [6]
    [5] [5] [5] [5] [1]
    [5] [5] [5] [1] [1]
    [5] [5] [1] [1] [1]
    [5] [1] [1] [1] [1]
    [4] [4] [4] [4] [2]
    [4] [4] [4] [2] [2]
    [4] [4] [2] [2] [2]
    [4] [2] [2] [2] [2]
    [3] [3] [3] [2] [1]
    [3] [3] [2] [2] [1]
    [3] [3] [2] [1] [1]
    [3] [2] [2] [2] [1]
    [3] [2] [2] [1] [1]
    [3] [2] [1] [1] [1]
    Is this difficult to calculate? (I don’t know much about probability theory)

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